4. A software engineer has the capability of thinking 100 lines of code in five minutes and
can type 100 lines of code in 10 minutes. He takes a break for five minutes after every ten
minutes. How many lines of codes will he complete typing after an hour?

Answer:
250 lines of codes

5. A man was engaged on a job for 30 days on the condition that he would get a wage of Rs.
10 for the day he works, but he have to pay a fine of Rs. 2 for each day of his absence. If he
gets Rs. 216 at the end, he was absent for work for … days.

Answer:
7 days

Explanation:
The equation portraying the given problem is:
10 * x – 2 * (30 – x) = 216 where x is the number of working days.
Solving this we get x = 23
Number of days he was absent was 7 (30-23) days.

6. A contractor agreeing to finish a work in 150 days, employed 75 men each working 8
hours daily. After 90 days, only 2/7 of the work was completed. Increasing the number of
men by ________ each working now for 10 hours daily, the work can be completed in time.

Answer:
150 men.

Explanation:
One day’s work = 2 / (7 * 90)
One hour’s work = 2 / (7 * 90 * 8)
One man’s work = 2 / (7 * 90 * 8 * 75)
The remaining work (5/7) has to be completed within 60 days, because the total
number of days allotted for the project is 150 days.
So we get the equation
(2 * 10 * x * 60) / (7 * 90 * 8 * 75) = 5/7 where x is the number of men
working after the 90th day.
We get x = 225
Since we have 75 men already, it is enough to add only 150 men.

7. what is a percent of b divided by b percent of a?
(a) a (b) b (c) 1 (d) 10 (d) 100

Answer:
(c) 1

Explanation:
a percent of b : (a/100) * b
b percent of a : (b/100) * a
a percent of b divided by b percent of a : ((a / 100 )*b) / (b/100) * a )) = 1

8. A man bought a horse and a cart. If he sold the horse at 10 % loss and the cart at 20 %
gain, he would not lose anything; but if he sold the horse at 5% loss and the cart at 5% gain,
he would lose Rs. 10 in the bargain. The amount paid by him was Rs._______ for the horse
and Rs.________ for the cart.

Answer:
Cost price of horse = Rs. 400 & the cost price of cart = 200.

Explanation:-
Let x be the cost price of the horse and y be the cost price of the cart.
In the first sale there is no loss or profit. (i.e.) The loss obtained is equal to the gain.
Therefore (10/100) * x = (20/100) * y
X = 2 * y —————–(1)
In the second sale, he lost Rs. 10. (i.e.) The loss is greater than the profit by Rs. 10.
Therefore (5 / 100) * x = (5 / 100) * y + 10 ——-(2)
Substituting (1) in (2) we get
(10 / 100) * y = (5 / 100) * y + 10
(5 / 100) * y = 10
y = 200
From (1) 2 * 200 = x = 400

9. A tennis marker is trying to put together a team of four players for a tennis tournament out
of seven available. males – a, b and c; females – m, n, o and p. All players are of equal ability
and there must be at least two males in the team. For a team of four, all players must be able
to play with each other under the following restrictions:
b should not play with m,
c should not play with p, and
a should not play with o.
Which of the following statements must be false?
1. b and p cannot be selected together
2. c and o cannot be selected together
3. c and n cannot be selected together.

Answer:
3.

Explanation:
Since inclusion of any male player will reject a female from the team. Since there
should be four member in the team and only three males are available, the girl, n should
included in the team always irrespective of others selection.

10. Five farmers have 7, 9, 11, 13 & 14 apple trees, respectively in their orchards. Last
year,each of them discovered that every tree in their own orchard bore exactly the same
number of apples. Further, if the third farmer gives one apple to the first, and the fifth gives
three to each of the second and the fourth, they would all have exactly the same number of
apples. What were the yields per tree in the orchards of the third and fourth farmers?

Answer:
5